If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4f^2-12f-7=0
a = 4; b = -12; c = -7;
Δ = b2-4ac
Δ = -122-4·4·(-7)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-16}{2*4}=\frac{-4}{8} =-1/2 $$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+16}{2*4}=\frac{28}{8} =3+1/2 $
| 4x-12=-2(6-2x) | | 3v+19+18v=-13+19v | | 4x+3+3x=15 | | 6-(1.8+3)=t | | 4-7a=16-3a | | 4x=2x^-9 | | x+.0925x=25 | | 18x-22=14 | | 22.59(10-y)+27.5=250 | | 13.78+9.4g=-16.25-7.2g+14.5g | | 200-5x=100 | | 8(r-810)=560 | | -20=w/2 | | x+41/8=11 | | 19(w+19)=798 | | 50=2n | | 4x-5x=-18 | | -18-7m=13m+18-17m | | x=21/8=9 | | a-(12)=6 | | −5+n/3=−8 | | 7(x+9)=2(9-x) | | 36k=–9 | | 2(4w+4=2(1+2w)+2w | | -11-5x=-9x+5 | | 2.38+x=6 | | 4(4x+1)=24 | | 4^(8x-4)=3 | | 4.03+5.41-19.2h=14.13-18.5h | | m/12=35 | | 28x=840 | | m/12=75 |